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rant1ng
6y

Hey... to somebody reading this, most likely.

The problem, is that you put if($var = 'something')
You need ==, not =.
Php doesn't tell you that though. It'll just change the var to 'something'

That's why you're getting that really obscure, doesn't make any sense error.

You're welcome.

rant

php wtf catch that
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Comments
  • 11
    6y
    Fun fact, what @irene is suggesting is a standard technique sometimes called Yoda notation or Yoda conditionals (because it's like Yoda's often-inverted grammar). Useful.
  • 3
    6y
    Same is with js and python when you want to send a function as argument and put the () behind them. It will just execute instead of pass through. Gave me plenty of headaches.
  • 2
    6y
    @RememberMe @irene I just googled that... I never knew about this.
  • 0
    6y
    Same with this..

    if(
    $someCheckVar
    && $weNeedThis = 'yo'
    ) // weneedthis: "yo"

    if(
    $weNeedThis = 'yo'
    && $someCheckVar
    ) // weneedthis: true
  • 0
    6y
    Use IDE. 😆
  • 2
    6y
    In C, you can do the same, but any decent C compiler will display a warning.
  • 3
    6y
    $var = 5..

    If you want it to be 7, you have to use = 7, not = 5.

    Php doesn’t tell you that..

    You’re welcome 😂
  • 0
    6y
    So cute
  • 0
    6y
    @just8littleBit 😂
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