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- 
				
				 leny4529ylet i = 0; leny4529ylet i = 0;
 
 while( i++ <= 100 ) {
 let message = "";
 
 i % 3 || ( message += "Fizz" );
 i % 5 || ( message += "Buzz" );
 
 console.log( message || i );
 }
- 
				
				You don't need a separate case for when Fizz and Buzz are together! (You probably do if you're using console.log. But there are other output functions that don't append a newline.)
- 
				
				for(var num = 0; num <= 100; num++) {
 var out = "";
 
 if(num % 3 == 0)
 out += "Fizz";
 
 if(num % 5 == 0)
 out += "Buzz";
 
 console.log(out || num);
 }
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Fizzbuzz
for (var num = 0; num <= 100; num++)
if (num % 3 == 0 && num % 5 == 0) {
console.log("FizzBuzz");
}
else if (num % 5 == 0) {
console.log("Buzz");
}
else if (num % 3 == 0) {
console.log("Fizz");
}
else {
console.log(num);
}
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javascript js
eloquentjava