Anyone know what identity this is?

(a+b)/(1/(a-b)) == a^2 - b^2

I just obtain the thingy of fraction a bit by flipping dem enumerator and sum denominator fr fr no cap gg.
Do dem thing with the left side fraction.
And tadaaa, have sum a^2 - b^2. Would say difference of dem squares

I learnt that as binomial theorems in 7th grade math.

(a + b)² = a² + 2ab + b² (first theorem)

(a - b)² = a² - 2ab + b² (second theorem)

(a + b)*(a -b) = a² - b² (third theorem, just get the (a-b) term out of the pointless double division in your case)

Just for the record, they are Newton's binomial theorems.

Thanks fastnop and core!

7th grade math in the inner city unfortunately did not teach binomials.

@retoor no cap gg. Utter cancer. Lol.

Dont ever change.

@Wisecrack tnx