16
whizNov
7y

Seems legit right πŸ€”

Comments
  • 5
    xkcd #221.
  • -1
    @7400
    1. Chosen by "a" fair dice is the condition for naive probability.
    2. "Guaranteed to be random" does not exist in computer.
    3. This solution only apply in frequentist statistics, but not Bayesian statistics. And even in frequentist space. It's a wrong answer, since the expectation for a fair dice is 3.5.
  • 5
    @sunfishcc you are fighting with a years old comic strip
  • 2
    @gorsamp 🀦‍β™‚οΈπŸ€¦‍β™‚οΈπŸ€¦‍♂️ I know
  • 2
    @sunfishcc I see, carry on then
  • 1
    @gorsamp Bayesian is fun stuffπŸ˜‰
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