Let's see the coder in you.
If I give input: 1 output: 2
If I give input: 2 output:1
Only these two test cases needed.
You should not use control structures such as if,else,for,while,switch etc. (The answer is simple) (Don't cheat)

int number;
cin>>number; //get number
cout<<??????; //Your code

There are even multiple solutions

So how do we go about this? If i do t comment my answer how will you see the coder in me?

@fox8091 Answer here
https://docs.google.com/forms/d/...

Upvote this comment so that everyone can know where to answer

Everyone knows the answer but when I give the link to the form to answer no one answers.

¯\_(ʘ_ʘ)_/¯

@Artemix I don't know how you did it. it's great Congo. Give your answers at form and comment on the rant. I will +1 your comment if answer was correct.

@Artemix I saw your answer, it's correct :) . The later part of my previous comment was for others who still have not answered.

Easy. Done!

@varundey It's correct, great! I get very different solutions. The solution can be still made neat. I will post my solution and all other solutions posted tomorrow.

@Amrish it's O(1) time and constant space. How can you make it more neat?

@varundey My bad, after all Xor seems to be faster than addition/subtraction.
¯\_(ツ)_/¯

Everyone is thinking too complex, the answer is extremely short

Variable - - ;

Did it ;)

Throwing my bit of a solution in...

@dfox how about the possibility to do some little code challenges?

@aul12 we definitely like that idea and we've been looking at some possible features along those lines.

submitted !

✌ done

Done, but I feel like that my answer is cheap :D

Solved with 2 chars (excluding variable name). Couldn't find shorter answer ¯\_(ツ)_/¯

Solved, I think? Mine was only one line, no extra variables...

Done!

I got this after 5 minutes fiddling with [The binary operator used has been redacted].

I almost didn't go to sleep because of this task. Nice challenge.

I look forward to new ones :D

Done

The hardest part was remembering the syntax as I don't use it ever in actual code :)

@Amrish when do you publish the submissions, interessted on different solutions

Commenting for notifications. Submitted

Done.

(Nombers%2)+1

Outpur = Input BIT-NAND 3 (Dec 3, binary 11)

Done.

cout<<3-number;

Done

I'll post mine, only because I doubt anyone went this route lol:

#include <iostream>
#include <math.h>
using namespace std;

int main()
{
int number;
cin >> number;
cout << floor(abs(tan(number)+.5)) << endl;
return 0;
}

Hi everyone. That was an overwhelming response. To my surprise I found more than 10 different correct solutions submitted!! Great!
I will post all the solutions within 5 hours. It's different time here (India), I just woke up.
I have not upvoted some comments cause I need a compiler to check them out. I have not upvoted if you had directly commented the answer.

This was fun -- more please?
And I thought I had a good solution...that 2 character solution is the best lol!

^ ?

@filthyranter heh, I meant XOR operator.

Hi everyone, follow the link to get all unique solutions given. I have attached repeated solutions too. Great work!

https://drive.google.com/open/...

I had no time to put a proper formatting
¯\_(ツ)_/¯ . Certain solutions were impressive 😎

Congo @Artemix @Varundey @aul12 @leriaz @TheSilent @cuboidcat @ste26054 @bukovles @W3D3 @vzqzac @Thaon @Gprabhat @asdf 😎 Thanks @dfox.Lets use #devcode tag for more of these :D

@alexanderholman you had to fill the answers in the form link I had given in my previous comments. :)

Top different solutions (filtered by timestamp for repetitive solutions)

@Artemix that was actually the solution I thought of first, but I decided there's a shorter way so I XORed with 3 because how often do you get a chance to use XOR? :)

@Bikonja XOR ROXOR!

@Artemix my second solution is more or less your solution

@filthyranter Sorry bro, I had missed out your solution, I scrutinized the results so fast (10 mins).

Solution: 1+(number != 2)
This solution is correct and unique 😎.

This makes 16 unique solutions 😎. Great work people!!

A simple 2/(input) should work.