I swear I NEVER hated PHP before, but after seeing this shit, I just can't love it anymore, I feel betrayed

I mean, WTF? Just bc I'm using the variable as a reference in the NEXT loop the LAST element changes? What even is the fucking reason?

Yeah, I read the answer on StackOverflow, but seriously...

SO ref: https://stackoverflow.com/questions...

It's kinda a bug, but it's also a reference in memory issue too, which is why I very rarely use variables by reference in php unless it's to conserve memory limits which I can't get around.

Basically, and if I go look at that link it's probably safe to say it says the same thing, you no longet have a localised variable for the scope of the foreach() as you pushed it as a reference giving the second $item an inherited value, you should unset() the first $item

Also, can you do my eyes a favour and hit the Enter key just before that ")" in your first array?

wait php doesn't use reference types like all the sane high level languages??

@inaba IIRC they are only value types and "references" which are actually aliases

My problem here is that $item is not scoped to the foreach. That really drives me nuts. That would make this behavior impossible and is in general what you actually expect.

@Lythenas indeed!

Bc rn all that can be done is using "unset($item)" after the first loop

@C0D4 I'm sorry about how that's written, I just screenshotted the question on SO.

@12bitfloat https://php.net/manual/en/...

> One of the key-points of PHP 5 OOP that is often mentioned is that "objects are passed by references by default".

Well that is how it's supposed to be I gue-

> This is not completely true. This

Oh- oh god

Never had to use such a foreach loop. Why care

@inaba I've generally gotten the impression that mistaking PHP for a sane language can lead to much mental anguish, and I've never used PHP. It's really it's own thing, design-wise.

It is not a bug. Read the accepted answer for the technical explanation.

If you want to avoid this, just use a different name for your references.

foreach($arr as &$ref) { ... } print_r($arr);

foreach($arr as $val) { ... } print_r($arr);

@nitnip I know I know, it's just that is not how most people think it should work

@nitnip "It's not a bug, it's just really stupid"